4x^2+50x+144=0

Solution for 4x^2+50x+144=0 equation:

4x^2+50x+144=0

a = 4; b = 50; c = +144;
Δ = b2-4ac
Δ = 502-4·4·144
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-14}{2*4}=\frac{-64}{8}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+14}{2*4}=\frac{-36}{8}
=-4+1/2
$